27/04/2018, 20:39

Bài 20 trang 18 Sách giáo khoa (SGK) Hình học 10 Nâng cao

Cho sáu điểm A, B, C, D, E, F. Chứng minh rằng ...

Cho sáu điểm A, B, C, D, E, F. Chứng minh rằng

Bài 20. Cho sáu điểm (A, B, C, D, E, F). Chứng minh rằng

(overrightarrow {AD}  + overrightarrow {BE}  + overrightarrow {CF}  = overrightarrow {AE}  + overrightarrow {BF}  + overrightarrow {CD}  = overrightarrow {AF}  + overrightarrow {BD}  + overrightarrow {CE} ).

Hướng dẫn trả lời

Theo quy tắc ba điểm, ta có

(eqalign{
& overrightarrow {AD} + overrightarrow {BE} + overrightarrow {CF} = left( {overrightarrow {AE} + overrightarrow {ED} } ight) + left( {overrightarrow {BF} + overrightarrow {FE} } ight) + left( {overrightarrow {CD} + overrightarrow {DF} } ight) cr
& ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, = overrightarrow {AE} + overrightarrow {BF} + overrightarrow {CD} + left( {overrightarrow {FE} + overrightarrow {ED} + overrightarrow {DF} } ight) cr
& ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, = overrightarrow {AE} + overrightarrow {BF} + overrightarrow {CD} + left( {overrightarrow {FD} + overrightarrow {DF} } ight) cr
& ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, = overrightarrow {AE} + overrightarrow {BF} + overrightarrow {CD} cr} )

Tương tự, ta cũng có

(eqalign{
& overrightarrow {AD} + overrightarrow {BE} + overrightarrow {CF} = left( {overrightarrow {AF} + overrightarrow {FD} } ight) + left( {overrightarrow {BD} + overrightarrow {DE} } ight) + left( {overrightarrow {CE} + overrightarrow {EF} } ight) cr
& ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, = overrightarrow {AF} + overrightarrow {BD} + overrightarrow {CE} + left( {overrightarrow {FD} + overrightarrow {DE} + overrightarrow {EF} } ight) cr
& ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, = overrightarrow {AF} + overrightarrow {BD} + overrightarrow {CE} + left( {overrightarrow {FE} + overrightarrow {EF} } ight) cr
& ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, = overrightarrow {AF} + overrightarrow {BD} + overrightarrow {CE} cr} )

Vậy ta có (overrightarrow {AD}  + overrightarrow {BE}  + overrightarrow {CF}  = overrightarrow {AE}  + overrightarrow {BF}  + overrightarrow {CD}  = overrightarrow {AF}  + overrightarrow {BD}  + overrightarrow {CE} )

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